Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 12

Answer

$q=9$

Work Step by Step

The given equation is $\Rightarrow 2\sqrt {q}+5=11$ Subtract $5$ from each side. $\Rightarrow 2\sqrt {q}+5-5=11-5$ Simplify. $\Rightarrow 2\sqrt {q}=6$ Divide each side by $2$. $\Rightarrow \frac{2\sqrt {q}}{2}=\frac{6}{2}$ Simplify. $\Rightarrow \sqrt {q}=3$ Square each side of the equation. $\Rightarrow (\sqrt{q})^2=3^2$ Simplify. $\Rightarrow q=9$ Check $q=9$. $\Rightarrow 2\sqrt {q}+5=11$ $\Rightarrow 2\sqrt {9}+5=11$ $\Rightarrow 2\sqrt {3^2}+5=11$ $\Rightarrow 2(3)+5=11$ $\Rightarrow 6+5=11$ $\Rightarrow 11=11$ True. Hence, the solution is $q=9$.
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