Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.3 - Solving Equations with Variables on Both Sides - Exercises - Page 24: 33

Answer

$4$ seconds

Work Step by Step

Let's note by $t$ the time (in seconds) needed by the cheetah to catch up to the antelope. The distance, $C$, travelled by the cheetah running at a speed of $90$ feet per second will be $90$ times $t$. Therefore $$C = 90t.\tag{1}$$ Similarly, the distance, $A$, travelled by the antelope running at $60$ feet per second in $t$ seconds will be $60t$. However, the antelope has a headstart of $120$ ft. Hence, the total distance the antelope travelled (from the origin point) is $60t + 120$. Therefore $$A = 60t + 120.\tag{2}$$ In order for the cheetah to catch up, the distances $C$ and $A$ should be equal. Therefore, we set up the equation $$C = A.\tag{3}$$ Using equations $(1)$ and $(2)$ in $(3)$ we have: $$\begin{align} 90t& = 60t + 120\\ 30t& = 120\\ t &= 4. \end{align}$$ Thus the time taken by cheetah to catch up is $4$ seconds.
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