Answer
$x \gt 0\\y \gt x \\ \pi y^2 \gt \pi x^2+10$.
Work Step by Step
The radius of the smaller circle is positive; this means that $x \gt 0$
The radius $y$ is for the larger circle; this means that $y \gt x$
The area of the larger circle is at least $10 \ sq \ unit$ greater; this means that $\pi y^2 \gt \pi x^2+10$.
Thus, the system is:
$x \gt 0\\y \gt x \\ \pi y^2 \gt \pi x^2+10$.
