Answer
$x=\dfrac{5}{3}; y=\dfrac{1}{3}; z=3$
Work Step by Step
Subtract the second equation from equation $1$.
$3y-3z=-8$
Subtract the equation from equation $3$.
This yields $z=3$
Plug the value of $z$ into the second equation, giving: $y=\dfrac{1}{3}$
Now, we will plug the value of $y$ and $z$ into the first equation to get the value of $x$.
$x+3+\dfrac{1}{3}=5 \\ \implies x=\dfrac{5}{3}$
Thus, $x=\dfrac{5}{3}; y=\dfrac{1}{3}; z=3$
