Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 9 - 9.2 - Two-Variable Linear Systems - 9.2 Exercises - Page 649: 62



Work Step by Step

Multiply the first equation by $2$ and multiply the second equation by $3$. Therefore, the system of two equations is: $30x+6y=12 \\ -30x+3ky=27$ Use $k=-2$ $30x+6y=12 \\ -30x+6y=27$ This yields an inconsistent system. So, we choose the value of $k$ as: $k=-2$
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