Answer
$k=-2$
Work Step by Step
Multiply the first equation by $2$ and multiply the second equation by $3$.
Therefore, the system of two equations is:
$30x+6y=12 \\ -30x+3ky=27$
Use $k=-2$
$30x+6y=12 \\ -30x+6y=27$
This yields an inconsistent system.
So, we choose the value of $k$ as: $k=-2$
