## Algebra and Trigonometry 10th Edition

$k=-2$
Multiply the first equation by $2$ and multiply the second equation by $3$. Therefore, the system of two equations is: $30x+6y=12 \\ -30x+3ky=27$ Use $k=-2$ $30x+6y=12 \\ -30x+6y=27$ This yields an inconsistent system. So, we choose the value of $k$ as: $k=-2$