Chapter 9 - 9.2 - Two Variable Linear Systems - 9.2 Exercises - Page 647: 35

$x=4; y=1$

Multiply the second equation by $5$, and then add the first equation to equation $2$. $3x-5y+10x+5y=7+45 $ The yields $x=4$ Now, we will plug the value of $x$ into the first equation to get the value of $y$. $3(4)-5y=7 \\ \implies y=1$ Thus, $x=4; y=1$