Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 9 - 9.1 - Linear and Nonlinear Systems of Equations - 9.1 Exercise - Page 636: 30


$(0,0),$ $(12,6)$

Work Step by Step

From the first equation, $x=2y$ (Isolation). Consider the second equation, $3x-y^{2}=0$ This becomes: $3(2y)-y^{2}=0$ (Substitution). Thus, $6y-y^{2}=0$ $y(6-y)=0$ This gives $y=0,$ and $y=6$ Accordingly, $x=0,$ and $x=12$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.