Answer
$\lt 30 \sqrt 2, 30 \sqrt 2 \gt $
Work Step by Step
We are given that $||\overrightarrow{v_{w}}|| = 60$ and
$ \theta = 45^{\circ}$
We know that $v_{w}=||v|| \lt \cos \theta , \sin \theta \gt $
Thus, $v_{w}=60 \lt \cos 45^{\circ} , \sin 45^{\circ} \gt \\=60 \lt \dfrac{\sqrt 2}{2}, \dfrac{\sqrt 2}{2} \gt \\= \lt 30 \sqrt 2, 30 \sqrt 2 \gt $
