Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Review Exercises - Page 553: 62



Work Step by Step

$cos(x+\frac{\pi}{6})-cos(x-\frac{\pi}{6})=1$ $cos~x~cos\frac{\pi}{6}-sin~x~sin\frac{\pi}{6}-(cos~x~cos\frac{\pi}{6}+sin~x~sin\frac{\pi}{6})=1$ $-2~sin~x~sin\frac{\pi}{6}=1$ $-2~sin~x~\frac{1}{2}=1$ $sin~x=-1$ $x=\frac{3\pi}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.