Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - 7.4 - Sum and Difference Formulas - 7.4 Exercises - Page 540: 98



Work Step by Step

We know that $\tan \theta=\dfrac{m_2-m_1}{1+m_1m_2}$ or, $\theta=tan^{-1} \dfrac{m_2-m_1}{1+m_1m_2}$ We need to plug data into the above expression. Now, $\theta=\tan^{-1} \dfrac{1-\dfrac{1}{\sqrt 3}}{1+(1)(\dfrac{1}{\sqrt 3})}$ or, $\theta=15^{\circ}$
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