Answer
False.
$\frac{5\pi}{6}$ does not lie in the range of $arcsinx$
Work Step by Step
The range of $y=arcsinx$ is $[-\frac{\pi}{2},\frac{\pi}{2}]$. then:
$arcsin(\frac{1}{2})=\frac{\pi}{6}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.6 - Inverse Trigonometric Functions - 6.6 Exercises - Page 487: 106
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