Answer
$θ=arcsin(\frac{1}{x+1})$
Work Step by Step
$sin~θ=\frac{opp}{hyp}$
$sin~θ=\frac{x-1}{x^2-1}=\frac{x-1}{x^2-1^2}=\frac{x-1}{(x+1)(x-1)}=\frac{1}{x+1}$
$θ=arcsin(\frac{1}{x+1})$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.6 - Inverse Trigonometric Functions - 6.6 Exercises - Page 484: 44
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