## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 6 - 6.5 - Graphs of Other Trigonometric Functions - 6.5 Exercises - Page 476: 61

#### Answer

The function is odd. Notice that the function is symmetric with respect to the origin. $f(-x)=-f(x)$, that is $-x+tan(-x)=-(x+tan~x)$

#### Work Step by Step

$f(x)=x+tan~x$ $f(-x)=-x+tan(-x)=-x+\frac{sin(-x)}{cos(-x)}=-x+\frac{-sin~x}{cos~x}=-x-tan~x=-(x+tan~x)=-f(x)$

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