Answer
$10$ cycles/min
Work Step by Step
Number~of~cycles~per~min$=\frac{1}{Period}=\frac{1}{6~\frac{sec}{cycle}}=\frac{1}{6}~\frac{cycle}{sec}\times\frac{60~sec}{1~min}=10~cycles/min$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.4 - Graphs of Sine and Cosine Functions - 6.4 Exercise - Page 466: 80b
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