## Algebra and Trigonometry 10th Edition

(a) $\frac{\pi}{12}$ lies in the First Quadrant. (b) $-\frac{11\pi}{9}$ lies in the Second Quadrant.
If $θ$ lies in the: - First Quadrant, then $0\ltθ\lt\frac{\pi}{2}$ - Second Quadrant, then $\frac{\pi}{2}\ltθ\lt\pi$ - Third Quadrant, then $\pi\ltθ\lt\frac{3\pi}{2}$ - Fourth Quadrant, then $\frac{3\pi}{2}\ltθ\lt2\pi$ (a) $0\lt\frac{\pi}{12}\lt\frac{\pi}{2}$ , so $\frac{\pi}{12}$ lies in the First Quadrant. (b) $-\frac{11\pi}{9}+2\pi=\frac{7\pi}{9}$ $\frac{\pi}{2}\lt\frac{7\pi}{9}\lt\pi$ , so $-\frac{11\pi}{9}$ lies in the Second Quadrant.