## Algebra and Trigonometry 10th Edition

$x=1$
$\frac{1}{3}=3^{-1}$ $(\frac{1}{3})^{x-3}=9$ $(3^{-1})^{x-3}=3^2$ $3^{-x+3}=3^2$ Using the One-to-One Property: $-x+3=2$ $-x=2-3=-1$ $x=1$