Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - P.S. Problem Solving - Page 420: 17


$x=1$ or $x=e^2=7.389$

Work Step by Step

Use the Power Property: $\ln x^2=2\ln x$ $(\ln x)^2=2\ln x$ $(\ln x)^2-2\ln x=0$ $(\ln x)(\ln x-2)=0$ First Solution: $\ln x=0$ $e^{\ln x}=e^0~~$ (Use the Inverse Property: $e^{\ln x}=x$): $x=1$ Second Solution: $\ln x-2=0$ $\ln x=2$ $e^{\ln x}=e^2~~$ (Use the Inverse Property: $e^{\ln x}=x$): $x=e^2=7.389$
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