Answer
$\ln\frac{x^6}{(x^2-1)^2}$
Work Step by Step
$2[3\ln x-\ln(x+1)-\ln(x-1)]=2[\ln x^3-\ln(x+1)-\ln(x-1)]=2\ln\frac{x^3}{(x+1)(x-1)}=2\ln\frac{x^3}{x^2-1}=\ln(\frac{x^3}{x^2-1})^2=\ln\frac{x^6}{(x^2-1)^2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.3 - Properties of Logarithms - 5.3 Exercises - Page 386: 74
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