## Algebra and Trigonometry 10th Edition

Center: $(2,-1)$ Vertices: $(-2,-1) , (6,-1)$ Foci: $(-3,-1) , (7,-1)$
The horizontal transverse axis is: $a=4; b=3$ The center of the hyperbola is: $(2,-1)$ Vertices: $(h \pm a , k)=(-2,-1) , (6,-1)$ Now, $c=\sqrt {a^2+b^2}=\sqrt {4^2+3^2}=5$ Foci: $(h \pm c , k)=(2 +5 , -1), (2 -5 , -1)=(-3,-1) , (7,-1)$