Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 340: 84



Work Step by Step

We have: $b^2=c^2-a^2=(150)^2-(93)^2=13851$ The equation of the parabola is: $\dfrac{x^2}{8649}-\dfrac{y^2}{13851}=1$ Substitute $y=75$ and solve for the positive value of $x$. $\dfrac{x^2}{8649}-\dfrac{(75)^2}{13851}=1$ or, $\dfrac{x^2}{8649}=1+\dfrac{5625}{13851}$ So, $x =\sqrt {8649 (1+\dfrac{5625}{13851})} \approx 110.279$
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