Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 340: 84

Answer

$110.279$

Work Step by Step

We have: $b^2=c^2-a^2=(150)^2-(93)^2=13851$ The equation of the parabola is: $\dfrac{x^2}{8649}-\dfrac{y^2}{13851}=1$ Substitute $y=75$ and solve for the positive value of $x$. $\dfrac{x^2}{8649}-\dfrac{(75)^2}{13851}=1$ or, $\dfrac{x^2}{8649}=1+\dfrac{5625}{13851}$ So, $x =\sqrt {8649 (1+\dfrac{5625}{13851})} \approx 110.279$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.