## Algebra and Trigonometry 10th Edition

(a) According to the graph, when $x=-1$, $y=0$. The x-intercept is: $(-1,0)$ (b) Algebraically $y=0$ when $x=-1$ The x-intercept is: $(-1,0)$
$y=\frac{x+1}{x-3}$ $0=\frac{x+1}{x-3}$ $x+1=0$ $x=-1$