Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - Chapter Test - Page 304: 3



Work Step by Step

$f(x)=a(x-k)^2+h~~$ (Standard form, where $(k,h)$ is the vertex) $f(x)=a(x-3)^2-6$ Use the point $(0,3)$ to find $a$: $3=a(0-3)^2-6$ $3+6=a(-3)^2$ $9=9a$ $a=1$ $f(x)=1(x-3)^2-6=(x-3)^2-6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.