## Algebra and Trigonometry 10th Edition

$f(x)=(x-3)^2-6$
$f(x)=a(x-k)^2+h~~$ (Standard form, where $(k,h)$ is the vertex) $f(x)=a(x-3)^2-6$ Use the point $(0,3)$ to find $a$: $3=a(0-3)^2-6$ $3+6=a(-3)^2$ $9=9a$ $a=1$ $f(x)=1(x-3)^2-6=(x-3)^2-6$