## Algebra and Trigonometry 10th Edition

False. In this case, $y$ is directly proportional to $z$
$a,b,c$ are constants. $y=a\frac{1}{x}$ $x=b\frac{1}{z}$. Replace this equation in the above equation. $y=a\frac{1}{b\frac{1}{z}}=\frac{a}{b}(1)\frac{z}{1}=\frac{a}{b}z$ $y=cz$, where $c=\frac{a}{b}$