## Algebra and Trigonometry 10th Edition

$6x^{2} + 25x + 74 + \frac{248}{x - 3}$
Since we are dividing by (x - 3) the zero of that x = 3 goes into the top left space. $\hspace{0mm}\underline{3|}\hspace{5mm}6\hspace{5mm}7\hspace{5mm}-1\hspace{5mm}26$ $\hspace{15mm}\underline{18\hspace{8mm}75\hspace{4mm}222}$ $\hspace{8mm}6\hspace{6mm}25\hspace{7mm}74\hspace{4mm}\underline{|248}$ Since the bottom right space has a 248, the remainder is 248.