## Algebra and Trigonometry 10th Edition

$y$ is not a function of $x$
Solve the equation for $y$: $16x-y^4=0$ $-y^4=-16x$ $y^4=16x$ $y=±\sqrt[4] {16x}$ $y=±2\sqrt[4] x$ So, for each value of $x$ in the domain, except $x=0$, we will find 2 different values of $y$. For example, if $x=81$: $y=±2\sqrt[4] {81}=±6$