Answer
x = 1
Work Step by Step
Determine the x value that minimizes t.
T = $\frac{\sqrt{x^2-6x+10}}{4} + \frac{\sqrt{x^2+4}}{2}, 0\leq x \leq3$
In part c) we graphed the equation. Notice from the graph that T attains its minimum value at x=1.
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