## Algebra and Trigonometry 10th Edition

$0 \lt x \lt 92.105$
Let $x$ be exhaust temperature and $y$ be the percent load. We have $y=0.03x^2+245.50; 0 \lt x \lt 100$ To compute inverse, we will have to interchange $x$ and $y$. $x=0.03y^2+245.50; 245.50 \lt x \lt 545.50$ Re-write as: $x-245.50=0.03; 245.50 \lt x \lt 545.50$ or, $y=\sqrt {\dfrac{x-245.50}{0.03}}; 245.5 \lt x \lt 545.5$ Now set $x=500$; $y=\sqrt {\dfrac{500-245.50}{0.03}} \approx 92.105$ $0 \lt x \lt 92.105$