Answer
$(A~o~r)(x)=\frac{\pi}{4}x^2$
It is the area $A$ of the circular base of the tank as a function of the length $x$ of sides of the square.
Work Step by Step
$(A~o~r)(x)=A(r(x))=A(\frac{x}{2})=\pi(\frac{x}{2})^2=\frac{\pi}{4}x^2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - 2.6 - Combinations of Functions: Composite Functions - 2.6 Exercises - Page 220: 61c
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