## Algebra and Trigonometry 10th Edition

$f(x)=\frac{1}{4}x^3$
Since $f(x)=x^3$ is the overall shape of the graph we will start with that: $f(x)=x^3$ Notice that the graph has been compressed vertically (by a factor of k). The function of the graph can be written as: $f(x)=kx^3$ Substitute in the point (2,2) to solve for k: $2=k(2^3)$ $2=k(8)$ $k=\frac{2}{8}=\frac{1}{4}$ So, the final equation: $f(x)=\frac{1}{4}x^3$