Answer
$f(x)=x^2$ is an even function as f(x)=f(-x)=$x^2$
$f(x)=x^3$ is an even function as f(x)=-f(-x)=$x^3$
Work Step by Step
$f(x)=x^2$ is an even function as f(x)=f(-x)=$x^2$
$f(x)=x^3$ is an even function as f(x)=-f(-x)=$x^3$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - 2.4 - A Library of Parent Functions - 2.4 Exercises - Page 204: 48d
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