Answer
$h^2+3hx+3x^2+3$
Work Step by Step
$f(x) =x^3+3x$
$\frac{f(h+x)-f(x)}{h}=\frac{((x+h)^3+3(x+3))-(x^3+3x)}{h}= \frac{h^3+3h^2x+3x^2h+3h}{h}=h^2+3hx+3x^2+3$
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