## Algebra and Trigonometry 10th Edition

(a) $q(2)=\frac{11}{4}$ (b) It is not possible. (c) $q(-x)=\frac{2x^2+3}{x^2}$
$q(t)=\frac{2t^2+3}{t^2}$ (a) $q(2)=\frac{2(2)^2+3}{2^2}=\frac{2(4)+3}{4}=\frac{11}{4}$ (b) $q(0)=\frac{2(0)^2+3}{0^2}=\frac{3}{0}$ (It is not possible to divide by $0$) (c) $q(-x)=\frac{2(-x)^2+3}{(-x)^2}=\frac{2x^2+3}{x^2}$