#### Answer

$120$ different ways.

#### Work Step by Step

The order in which the 3 applicants are selected is not important. It is a combination of 3 applicants from a group of 10 applicants.
$_{10}C_3=\frac{10!}{(10-3)!·3!}=\frac{10\times9\times8\times7!}{7!\times3\times2\times1}=120$