#### Answer

$\frac{1}{120}$

#### Work Step by Step

We know that $probability=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}$
The number of all outcomes is $5!=120$ (same as $_5P_5$ because we place $5$ digits to $5$ places and the order matters)
There is $1$ "good outcome."
Hence the probability here is: $\frac{1}{120}$