Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.7 - Probability - 11.7 Exercises - Page 834: 34



Work Step by Step

From Exercises 31 and 32, $P(\text{both red})=\frac{1}{5}$, $P(\text{both yellow})=\frac{1}{15}$, thus $P(\text{both same colour})=\frac{1}{5}+\frac{1}{15}=\frac{3}{15}+\frac{1}{15}=\frac{4}{15}$ $P(\text{different colour})=1-P(\text{both same colour})=1-\frac{4}{15}=\frac{11}{15}$
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