Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.2 - Arithmetic Sequences and Partial Sums - 11.2 Exercises - Page 788: 87b

Answer

See below.

Work Step by Step

As we can see the sums of the first $n$ consecutive odd integers is $n^2$. We have $7$ terms, thus the sum is $7^2=49$. $1+3+5+7+9+11+13=49$
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