## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 10 - Review Exercises - Page 762: 78

#### Answer

No inverse is possible. (Not Invertible)

#### Work Step by Step

The general form of a matrix of order $2 \times 2$ is: $det \ A=\begin{bmatrix} p & q \\ r & s\end{bmatrix}=ps-qr$ We can determine the inverse of matrix $A$ as follows: $A^{-1}=\dfrac{1}{det \ A} \begin{bmatrix} s & -q \\ -r & p\end{bmatrix}$ Now, $det \ A =\begin{bmatrix} -18 & -15 \\ -6 & -5 \end{bmatrix}=90-90= 0$ This means that no inverse is possible.

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