Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 10 - 10.4 - The Determinant of a Square Matrix - 10.4 Exercises - Page 743: 84

Answer

$-1,3$

Work Step by Step

The determinant of a $2 \times 2$ matrix can be computed by using the formula $det =ps-qr$ where $det =\begin{bmatrix}p & q \\ r & s\end{bmatrix}$ After simplifying, this matrix yields: $0=(x)(x-2) - (-1)(-3) $ We need to set the expression equal to $0$. Thus, we have: $x^2-2x-3=0$ or, $(x-3)(x+1)=0$ So, $x=-1,3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.