Answer
{$-7-\sqrt {13}, -7+\sqrt {13}$}
Work Step by Step
$(z+6)^2=-2z$
$z^2+12z+36=-2z$
$z^2+14z+36=0$
$z^2+14z+49=13$
$(z+7)^2=13$
$z+7=+\sqrt {13} or -\sqrt {13}$
z = {$-7-\sqrt {13}, -7+\sqrt {13}$}
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 111: 88
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