## Algebra and Trigonometry 10th Edition

Area of a circle with radius of 2 inches: $A=\pi2^2=4\pi~in^2$ Area of a square with a side length of 4 inches. $A=l^2=4^2=16~in^2$ We know that $\pi=3.14...$ So: $\pi\lt4$ $4\pi\lt4\times4$ $4\pi\lt16$