Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.1 - Graphs of Equations - 1.1 Exercises - Page 80: 77c

Answer

Graphically: $1964$ Algebraically: $1964$

Work Step by Step

From the graph as shown, at $t=70.1$, $y\approx24$. Then, the year is: $$y=1940+24=1964$$ Verifying algebraically: $$70.1=\frac{63.6+0.97t}{1+0.01t}$$ $$70.1(1+0.01t)=63.6+0.97$$ $$70.1+0.701t=63.6+0.97t$$ $$-0.269t=-6.5$$ $$t=\frac{-6.5}{-0.269}\approx24$$ $$t=1940+24=1964$$ Thus, the answer $1964$ is verified algebraically.
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