## Algebra and Trigonometry 10th Edition

$x=17; y=-11; z=-3$
Plug the value of $z=-3$ into the second equation. $3y-8(-3)=-9 \implies y=-11$ Now, we will plug the value of $y$ and $z$ into the expression of $x$ to find the value of $x$. We get: $x-(-11)+2(-3)=22 \implies x=17$ Thus, $x=17; y=-11; z=-3$