## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter R - Section R.2 - Fractions - Practice: 20

#### Answer

$\frac{1}{5}$

#### Work Step by Step

1. Find LCD of fractions: 15 2. Write fractions with LCD as denominator: $\frac{8}{15}$ $\frac{1}{3} * \frac{5}{5} = \frac{5}{15}$ 3. Subtract numerators and keep common denominator of fractions: $\frac{8}{15} - \frac{5}{15} = \frac{3}{15} = \frac{1}{5}$

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