## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter R - Section R.2 - Fractions - Practice - Page R-13: 19

#### Answer

$\frac{17}{40}$

#### Work Step by Step

1. Find LCD of fractions: 40 2. Write both fractions with denominators of 40: $\frac{3}{8} * \frac{5}{5} = \frac{15}{40}$ $\frac{1}{20} * \frac{2}{2} = \frac{2}{40}$ 3. Solve by adding numerators together: $\frac{15}{40}$ + $\frac{2}{40}$ = $\frac{17}{40}$

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