## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter R - Section R.2 - Fractions - Exercise Set - Page R-16: 56

#### Answer

10$\frac{1}{60}$

#### Work Step by Step

1.Convert mix numbers to improper fractions. 7$\frac{3}{20}$ + 2$\frac{13}{15}$ = $\frac{143}{20}$ + $\frac{43}{15}$ 2.Convert the improper fractions into equivalent fractions using the LCD as the denominator. $\frac{143*3}{20*3}$ + $\frac{43*4}{15*4}$ = $\frac{429}{60}$ + $\frac{172}{60}$ 3.Add the numerators. $\frac{429}{60}$ + $\frac{172}{60}$ = $\frac{601}{60}$ = 10$\frac{1}{60}$

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