Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.2 - Fractions - Exercise Set: 49

Answer

$1 \frac{2}{21}$

Work Step by Step

1. Find LCD of fractions: The LCD of 3 and 7 is 21. 2. Write as equivalent fractions with denominator of 60. $\frac{2*7}{3*7} + \frac{3*3}{7*3} = \frac{14}{21} + \frac{9}{21}$ 3. Subtract numerators. $\frac{14+9}{21} = \frac{23}{21} = 1 + \frac{2}{21} = 1 \frac{2}{21}$
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