Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.4 - Variation and Problem Solving - Exercise Set - Page 665: 56


$C=8\pi$ in. $A=16\pi$ in.$^2$

Work Step by Step

$C=2\pi r$ $C=2\pi (4)$ $C=8\pi$ $A=\pi r^2$ $A=\pi (4)^2$ $A=16\pi$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.