Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.4 - Variation and Problem Solving - Exercise Set: 44

Answer

$90$ horsepower

Work Step by Step

Let $h$ be the horsepower. Let $r$ be the number of revolutions per minute. Let $d$ be the diameter of the shaft. $h=krd^3$ $h=40; r=120; d=2$ $40=k(120)(2)^3$ $k=\frac{1}{24}$ $h=\frac{1}{24}rd^3$ $r=80; d=3$ $h=\frac{1}{24}(80)(3)^3$ $h=90$ horsepower
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.