Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Section 9.4 - Variation and Problem Solving - Exercise Set - Page 665: 44


$90$ horsepower

Work Step by Step

Let $h$ be the horsepower. Let $r$ be the number of revolutions per minute. Let $d$ be the diameter of the shaft. $h=krd^3$ $h=40; r=120; d=2$ $40=k(120)(2)^3$ $k=\frac{1}{24}$ $h=\frac{1}{24}rd^3$ $r=80; d=3$ $h=\frac{1}{24}(80)(3)^3$ $h=90$ horsepower
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