Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 9 - Cumulative Review - Page 677: 32



Work Step by Step

$\frac{(3a^{-2}b)^{-2}}{(2ab^{-3})^{-3}}$ $=\frac{3^{-2}a^{4}b^{-2}}{2^{-3}a^{-3}b^{9}}$ $=\frac{1}{3^2}(2^3)(a^{4-(-3)})(b^{-2-9})$ $=\frac{2^3}{3^2}(a^7)(b^{-11})$ $=\frac{8a^7}{9b^{11}}$
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