#### Answer

$x=0,-\frac{1}{3}, 3$

#### Work Step by Step

$2x(3x+1)(x-3)=0$
$2x=0$
$x=0$
$3x+1=0$
$3x=-1$
$x=-\frac{1}{3}$
$x-3=0$
$x=3$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$x=0,-\frac{1}{3}, 3$

$2x(3x+1)(x-3)=0$
$2x=0$
$x=0$
$3x+1=0$
$3x=-1$
$x=-\frac{1}{3}$
$x-3=0$
$x=3$

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